0=16x^2+96x+4

Solution for 0=16x^2+96x+4 equation:

0=16x^2+96x+4

We move all terms to the left:

0-(16x^2+96x+4)=0

We add all the numbers together, and all the variables

-(16x^2+96x+4)=0

We get rid of parentheses

-16x^2-96x-4=0

a = -16; b = -96; c = -4;
Δ = b2-4ac
Δ = -962-4·(-16)·(-4)
Δ = 8960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8960}=\sqrt{256*35}=\sqrt{256}*\sqrt{35}=16\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-16\sqrt{35}}{2*-16}=\frac{96-16\sqrt{35}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+16\sqrt{35}}{2*-16}=\frac{96+16\sqrt{35}}{-32}
$